SOLUTION: What is an equation of the line through the point (-6,6) and perpendicular
to -5x-4y=6
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Question 188058: What is an equation of the line through the point (-6,6) and perpendicular
to -5x-4y=6
Answer by jojo14344(1513) (Show Source): You can put this solution on YOUR website!
We'll see the Slope of line -5x-4y=6 via Slope-Intercept Form, :
Arranging the variables,
, divide by 4
===> ===>
It's Slope=m1= -5/4
*Remember, for perpendicular lines,
The, line passing thru point (-6,6) has slope=m2=4/5, and via Slope-Intercept Form:
----> Y-Intercept
The Line Eqn follows===> y=(4/5)x+(54/5), Or in Standard From, (-4/5)x+y=54/5. Remove fraction by multiplying the eqn by "5":
-4x+5y=54 , Answer
Thank you,
Jojo
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