SOLUTION: The equation of the line that goes through the point ( 2, 5 ) is parallel to the line going through the points ( -1 ,2 ) and ( 1 ,6 ) is written in the form y = mx+b where m is:

Question 184085: The equation of the line that goes through the point ( 2, 5 ) is parallel to the line going through the points ( -1 ,2 ) and ( 1 ,6 ) is written in the form y = mx+b where
m is:
and b is:
Answer by jojo14344(1513) (Show Source): You can put this solution on YOUR website!

The equation of the line that goes through the point ( 2, 5 ) is parallel to the line going through the points ( -1 ,2 ) and ( 1 ,6 ) is written in the form y = mx+b where
m is:
and b is:
Important:
We know when 2 lines are parallel, their is the same:
Solving for , via Point-Slope Form
Thru points (-1,2) & (1,6):
---> REMEMBER.
Then Via Slope-Intercept Form: on point (2,5):

, Y-Intercept
Then it follows eqn (thru point (2,5))-->
In doubt? We'll see the graph:

To see the line passing thru points (-1,2) & (1,6)
Slope-Intercept form,
@ point (-1,2)
--->
@ point (1,6)
--->
It follows-------->
And we see the graph:

Thank you,
Jojo
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