# SOLUTION: If a bacteria population starts with 100 bacteria and doubles every three hours, then the number of bacteria after t hours is n=f(t)=100(2 to the t/3 power). When will the populati

Algebra ->  Algebra  -> Functions -> SOLUTION: If a bacteria population starts with 100 bacteria and doubles every three hours, then the number of bacteria after t hours is n=f(t)=100(2 to the t/3 power). When will the populati      Log On

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 Click here to see ALL problems on Functions Question 177896: If a bacteria population starts with 100 bacteria and doubles every three hours, then the number of bacteria after t hours is n=f(t)=100(2 to the t/3 power). When will the population reach 50,000?Answer by stanbon(57384)   (Show Source): You can put this solution on YOUR website!If a bacteria population starts with 100 bacteria and doubles every three hours, then the number of bacteria after t hours is n=f(t)=100(2 to the t/3 power). When will the population reach 50,000? --------------------- 50,000 = 100(2)^(t/3) 2^(t/3) = 500 Take the log of both sides to get: (t/3)log2 = log500 t/3 = log(500)/log(2) t/3 = 8.9657.. t = 26.9 hours =================== Cheers, Stan H.