SOLUTION: If the function G(x) = (x - 8)2 + 6 has the same shape as F(x) = x2 + 6, how far to the right of F(x) is G(x) shifted?

Question 176630: If the function G(x) = (x - 8)2 + 6 has the same shape as F(x) = x2 + 6, how far to the right of F(x) is G(x) shifted?
Answer by gonzo(654) (Show Source): You can put this solution on YOUR website!
i presume you mean and

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when x = 0, g(x) = (-8)^2 - 6 = 64 - 6 = 58
when x = 0, f(x) = (0 - 6 = -6
when f(x) = -6, x = 0
when g(x) = -6, x = 8
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one of the general forms of quadratic equation is:

where (h,k) is the vertex which is the turning point of the equation.
with f(x), h was 0 and k was -6
with g(x), h was 8 and k was -6
looks like g(x) was shifted 8 units to the right.
graph of both equations follows:
f(x) is -6 when x = 0
g(x) is 58 when x = 0
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