SOLUTION: f(x)=-3x+4 g(x)=3x+3 (g-f)(x)= g(x)= 3x+3 f(x)= -3x+4 therefore: (g-f)(x)= 3x+3 -(-3x+4) subtraction of g(x)-f(x) = 3x+3+3x+4 final result = 6x+7 (g+f)

Algebra ->  Algebra  -> Functions -> SOLUTION: f(x)=-3x+4 g(x)=3x+3 (g-f)(x)= g(x)= 3x+3 f(x)= -3x+4 therefore: (g-f)(x)= 3x+3 -(-3x+4) subtraction of g(x)-f(x) = 3x+3+3x+4 final result = 6x+7 (g+f)      Log On

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Question 17275: f(x)=-3x+4
g(x)=3x+3

(g-f)(x)=
g(x)= 3x+3
f(x)= -3x+4
therefore: (g-f)(x)= 3x+3 -(-3x+4)
subtraction of g(x)-f(x) = 3x+3+3x+4
final result = 6x+7

(g+f)(x)=
g(x)= 3x+3
f(x)= -3x+4
therefore: (g+f)(x) = 3x+3 +(-3x+4)
sum of g(x)+f(x) = 3x+3-3x+4
final result = 7

(g*f)(x)=
g(x)= 3x+3
f(x)= -3x+4
therefore: (g*f)(x)= (3x+3)*(-3x+4)
product of (g*f)(x)= -9x²+12x-9x+12
simple answer = -9x²+3x+12
factorial answer = (-9x+12)*(x+1)
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