SOLUTION: I looked at all the answers and still cannot figure it out. The question is: Given the function f(x) = x^2 + 3x + 4 , find the value of f(�1). So, I think I am lost. I did it

Question 169876: I looked at all the answers and still cannot figure it out. The question is:
Given the function f(x) = x^2 + 3x + 4 , find the value of f(�1). So, I think I am lost. I did it like this:
fx=x^2+3x+3
fx-2^2-3x-3=0
x=0
However, that is not the answer. The answer is supposed to be f(�1) = 2.
I would appreciate it if you would show me how to resolve this. Thank you.

Found 2 solutions by chiefman, gonzo:
Answer by chiefman(11) (Show Source): You can put this solution on YOUR website!
f(x)=x^2+3x+4 evaluating f(-1) wehave
f(-1)=(-1)^2+3(-1)+4 ie you equate x with -1
this gives
=1+(-3)+4
=2
hence f(-1) is 2
Answer by gonzo(654) (Show Source): You can put this solution on YOUR website!
if f(x) = x^2 + 3x + 3, then.....
f(-1) = (-1)^2 + 3*(-1) + 4
= 1 -3 + 4
= -2 + 4
= 2
-----
you just replace x with (-1) and solve.
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