Questions on Algebra: Functions, Domain, NOT graphing answered by real tutors!

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Question 166993: write an expression of the line containing the given point and perpendicular to the given line. Express the answer as y=mx+b. Simplify your answer.
(6,8);9x+y=2
y=-9x+2
y=1/9(x-x1)
y-y1= 1/9(x-x1)
y-8= 1/9(x-6)
This is where I get lost. I know that 1/9 is the slope, but when I multiply it by what is in the parenthesis and then subtract or add 8, I keep getting it wrong.
: write an expression of the line containing the given point and perpendicular to the given line. Express the answer as y=mx+b. Simplify your answer.
(6,8);9x+y=2
y=-9x+2
y=1/9(x-x1)
y-y1= 1/9(x-x1)
y-8= 1/9(x-6)
This is where I get lost. I know that 1/9 is the slope, but when I multiply it by what is in the parenthesis and then subtract or add 8, I keep getting it wrong.

Answer by Fombitz(1778) About Me  (Show Source):
You can put this solution on YOUR website!
y-8= (1/9)(x-6)
9(y-8)=x-6 Multiply both sides by 9 first.
9y-72=x-6Distribute 9 on the left hand side.
9y=x-6+72 Add 72 to both sides.
9y=x+66 Simplify.
y=(x+66)/9 Divide by 9.
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.
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Here's the two lines graphed and point (6,8) shown.
drawing( 300, 300, -2, 9, -2, 9,grid( 1 ),circle( 6, 8, .2 ), graph( 300, 300, -2, 9, -2, 9, (x+66)/9, -9x+2<BR>
))