SOLUTION: The funtions are f(x)=2x^2+5x+7 and g(x)=x^3 + 2 The directions say evaluate the following: and identify the domain of each The question is (f/g)(x) I got 2x^2+5x+7/x^3+2 would

Question 162733: The funtions are f(x)=2x^2+5x+7 and g(x)=x^3 + 2
The directions say evaluate the following: and identify the domain of each
The question is (f/g)(x)
I got 2x^2+5x+7/x^3+2 would the domain be that x cant equal 2?
Answer by gonzo(654) (Show Source): You can put this solution on YOUR website!
The funtions are f(x)=2x^2+5x+7 and g(x)=x^3 + 2
The directions say evaluate the following: and identify the domain of each
The question is (f/g)(x)
I got 2x^2+5x+7/x^3+2 would the domain be that x cant equal 2?
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f/g(x) = f(x)/g(x) so that part is correct.
the domain of f(x) and the domain of g(x) is the set of all real numbers.
the domain of f(x)/g(x) should be all all real numbers with the exception that the denominator can't be 0.
the denominator is 0 when g(x) is 0.
g(x) is 0 when x^3 is -2.
x^3 is -2 when x = cube root of -2.
the domain of f/g(x) is all values of x except cube root of -2.
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that's what i think.
looks like you had the right idea.

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