SOLUTION: please help with homework 1) is the relation xy=5 a function within the domain(-5,-1) 2)f(x)=4x^2-2x-6 and g(x)=2x-3 find the domain of (f-g)(x) and (f/g)(x) 3)find two numbers

Question 154177: please help with homework
1) is the relation xy=5 a function within the domain(-5,-1)
2)f(x)=4x^2-2x-6 and g(x)=2x-3 find the domain of (f-g)(x) and (f/g)(x)
3)find two numbers Y such that the distance from (-3,2)to (5,Y)is 10
4)Parallel to the line 2x-3y+4=0 passing through the origin
5)slope passing through the points (5,4)
6)A line passing through the points (7,-3)and(1,3).find standard form of the line and the linear function define by f(x)=mx+b that has the line as its graph.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
1) is the relation xy=5 a function within the domain(-5,-1)
Ans: yes

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2)f(x)=4x^2-2x-6 and g(x)=2x-3 find the domain of (f-g)(x) and (f/g)(x)
(f-g)(x+ - f(x)-g(x) = 4x^2-3
Domain: All Real Numbers
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(f/g)(x) = (4x^2-2x-6)/(2x-3)
Domain: All Real Numbers except x = 3/2
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3)find two numbers Y such that the distance from (-3,2)to (5,Y)is 10
(y-2)^2 + (5--3)^2 = 10^2
(y-2)^2 + 64 = 100
(y-2)^2 = 36
y-2 = 6 or y-2 = -6
y = 8 or y = -4
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4)Parallel to the line 2x-3y+4=0 passing through the origin
slope = (2/3)
EQUATIOn: y = (2/3)x
----------------------
5)slope passing through the points (5,4)
4/5
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6)A line passing through the points (7,-3)and(1,3).find standard form of the line and the linear function define by f(x)=mx+b that has the line as its graph.
slope = 6/6 = 1
interdept: 3 = 1 + b
b = 2
EQUATION:
y = x + 2
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Cheers,
Stan H.

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