SOLUTION: I need to solve this help solving these two problems, I am stuck I came up with x=2 for the first and (-3,1) for the second can you please help. 1. If {{{f(x)=4x^2-3x+2}}}, find f

Question 147158: I need to solve this help solving these two problems, I am stuck I came up with x=2 for the first and (-3,1) for the second can you please help.
1. If , find f(-1). I know this is not an equation just simplify.
2. State the domain of f(x)=(x+3)/(x-1)
I would greatly appreciate all the help I can get on these two. I am in College Algebra the text is College Algebra mac2105, Keiser University
Thank you
Teri
Found 2 solutions by nerdybill, mangopeeler07:
Answer by nerdybill(7384) (Show Source): You can put this solution on YOUR website!
1. If f(x)=4x^2-3x+2, find f(-1)
All you need to do is replace x with -1 and solve:
f(x)=4x^2-3x+2
f(-1)=4(-1)^2-3(-1)+2
f(-1)=4+3+2
f(-1)=9
.
2. State the domain of f(x)=(x+3)/(x-1)
Domain specifies all values of x for this equation.
The ONLY time this equation will NOT be defined is IF the denominator (x-1) goes to zero.
Therefore, to find where this equation is NOT defined set it to zero and solve:
x-1=0
x = 1
.
From the above,
domain of x is "all real numbers EXCEPT 1"

Answer by mangopeeler07(462) (Show Source): You can put this solution on YOUR website!
1. for f(-1) your corresponding range should be 9, because . so . f(-1)=9. That means that when x is -1, y should be 9.
2. . Your domain for this problem would be any value for x that does not make the denominator zero. So to figure this out, just take a shortcut and find out what will make the denominator zero, and say that the domain is any value for x except that one. In this case, to make the denominator of zero, you would have to ask yourself, what minus one would give me zero? Of course your answer is one, so your domain would be all x except 1.
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