# SOLUTION: find domain and range f(x)=2-square root xsquared+3x+2divided by x squared+5x+4

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 Question 143555: find domain and range f(x)=2-square root xsquared+3x+2divided by x squared+5x+4Answer by stanbon(57337)   (Show Source): You can put this solution on YOUR website!find domain and range f(x)=2-square root xsquared+3x+2divided by x squared+5x+4 ---------------- y = [2*sqrt(x^2+3x+2)] / [x^2+5x+4] y = [2*sqrt[(x+1)(x+2)] / [(x+4)(x+1)] ------------------- Domain: x cannot be -1 or -4 x^2+3x+2 must not be negative; but it never is. So, domain is "all Real Numbers except x=-1 and x=-4". --------------- Range: With those asymptotes all y values are possible So, range is "all Real Numbers". ================== Cheers, Stan H.