SOLUTION: Find the MINIMUM VALUE of Y if: Y = x^2 - 8x + 9
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Question 133948
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Find the MINIMUM VALUE of Y if: Y = x^2 - 8x + 9
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Answer by
checkley71(8403)
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Y=X^2-8X+9
(graph 300x200 pixels, x from -6 to 10, y from -10 to 10, x^2 -8x +9).
MINIMUM VALUE FOR Y=(4,-7)