SOLUTION: Please help me! Cannot figure this out. it says: without drawing the graph of the given equation,determine a)how many x-intercepts the parabola has b)whether its vertex lies above

Question 131282This question is from textbook structure and method
: Please help me! Cannot figure this out. it says: without drawing the graph of the given equation,determine a)how many x-intercepts the parabola has b)whether its vertex lies above or below or on the x-axis.
y=-x^2+2x-1
Please and THank you=) This question is from textbook structure and method

Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
The equation is in the form

The vertex will be at (-(b/2a), y) where you figure out the
x-coordinate first, then figure out the y-coordinate

Now plug into the equation to find the y-coordinate
of the vertex.

So, the vertex is at (1,0), which means it touches the x-axis
at 1 point only
Because is negative, the parabola opens down, like a cup
spilling out it's water. Therefore it lies below the x-axis
I'll graph it just to make sure

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