SOLUTION: A hot-air balloon is released at 1:00 P.M. and rises vertically at a rate of 4 meters/sec . An observation point is situated at 125 meters from a point on the ground directly belo

Question 127638This question is from textbook algebra and trigonometry with analiytic geometry
: A hot-air balloon is released at 1:00 P.M. and rises vertically at a rate of 4 meters/sec . An observation point is situated at 125 meters from a point on the ground directly below the balloon (see the figure). If t denotes the time (in seconds) after 1:00 P.M., express the distance d between the balloon and the observation point as a function of t.
Please use the notation "sqr(a)" which equals PLEASE PLEASE, HELPThis question is from textbook algebra and trigonometry with analiytic geometry

Answer by josmiceli(6783) (Show Source):
You can put this solution on YOUR website!
The observation point, the point directly below and the
height of the ballon form a right triangle. The distance
from the observer to the ballon is the hypotenuse
where distances are in meters
The ballon is going up at a rate of 4 m/sec. If
is the elapsed time, where is in seconds
and is in meters.

meters answer