SOLUTION: Let f(X)=[-x-3 , x<-1 , cubic root of x , -1<=x<2 , x^2-x , x>=2].Find f(-1) , f(1) , f(2)

Question 1197856: Let f(X)=[-x-3 , x<-1 , cubic root of x , -1<=x<2 , x^2-x , x>=2].Find f(-1) , f(1) , f(2)
Found 2 solutions by MathLover1, math_tutor2020:
Answer by MathLover1(20850) (Show Source): You can put this solution on YOUR website!
Piecewise[{{ , }, { }, { , } }]

Find
f(-1) ->use ,because
f(1) ->use ,because
f(2) ->use , because

Answer by math_tutor2020(3817) (Show Source): You can put this solution on YOUR website!

The tutor @MathLover1 is 2/3 correct.
f(1) and f(2) are correct, but f(-1) is not.

To compute f(-1), you should use since that applies for which is where x = -1 resides.

IF was , then you would use the first piece. However, we don't have the "or equal to" portion.

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