SOLUTION: Let f(x)=[-x-3 , cubic root of x, x^2-x, x < -1, -1 < or equal x < 2, x

SOLUTION: Let f(x)=[-x-3 , cubic root of x, x^2-x, x < -1, -1 < or equal x < 2, x > or equal 2 Find f(-1), f(1), and f(2)

Question 1197822: Let f(x)=[-x-3 , cubic root of x, x^2-x, x < -1, -1 < or equal x < 2, x > or equal 2
Find f(-1), f(1), and f(2)
Answer by math_tutor2020(3817) (Show Source): You can put this solution on YOUR website!

Some of what you typed in is a bit garbled. But I'm assuming this is what the piecewise function should look like

If my assumption is incorrect, then please let me know.

That piecewise function breaks down into 3 cases.
Case A: If then
OR
Case B: If then
OR
Case C: If then
We can only pick exactly one case. This is because each interval mentioned has no overlap with any other.
There's no way, for instance, to have x be something smaller than -1 and larger than 2 at the same time.

To compute f(-1) we plug in x = -1
The input x = -1 fits the description of case B since -1 is in the interval
I.e. is a true statement.

We'll plug x = -1 into the second piece.

-----------------------------------------

Now let's compute f(1).

The input x = 1 fits the interval so we'll go for case B again.

-----------------------------------------

Lastly let's find f(2).
The input x = 2 fits the interval .
We'll go for case C this time.

-----------------------------------------

Summary:
f(-1) = -1
f(1) = 1
f(2) = 2

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