SOLUTION: The equation sec x=−0.5 does NOT have a solution because
it means that cos x = −2 which is outside the range
of the negative value on the right side
the equation is
Algebra.Com
Question 1182118: The equation sec x=−0.5 does NOT have a solution because
it means that cos x = −2 which is outside the range
of the negative value on the right side
the equation is not well formulated
it means that sin x = −2 which is outside the range
Answer by math_tutor2020(3817) (Show Source): You can put this solution on YOUR website!
If sec(x) = -0.5, then cos(x) = -2 if we apply the reciprocal to both sides. Recall that sec = 1/cos.
Also, recall that the range for cosine is . Meaning that cos(x) between -1 and 1 inclusive of both endpoints. The value -2 is outside this interval, so it's impossible to have cos(x) = -2 where x is a real number.
RELATED QUESTIONS
Find the solution of the equation for [0,2pi]
2(tan(theta))-(sec^2(theta))=0
Here... (answered by Alan3354)
what is the solution set of all angles in [0,2pi)
4 cos^2x-3=0
5 sec^2x-20=0
(answered by stanbon)
if sec x + cos x =5/2 then find the value of sec x - cos x
(answered by Alan3354)
Which of the following equation has greatest and smallest number of real solutions?
(a) (answered by MathLover1)
Please Help!!!!
Which of the following is equivalent to 1/(1-cos(x))- 1/(1+cos(x))?
A)... (answered by Alan3354,Edwin McCravy)
Please help me solve this equation:
Which of the following is a valid trigonometric... (answered by lwsshak3)
Please Help!!!!
Which of the following is equivalent to 1/(1-cos(x))- 1/(1+cos(x))?
A)... (answered by Alan3354)
Name all values of θ for which y=secθ is undefined. Give the answer in radians.
(answered by Alan3354)
How do you determine the range of a bottom-heavy rational function? The function I need... (answered by josgarithmetic)
Find all solutions of the equation in the interval [0, 2π)
5 sec^2 x − 5 = 0
(answered by Alan3354)