SOLUTION: The equation sec x=−0.5 does NOT have a solution because it means that cos x = −2 which is outside the range of the negative value on the right side the equation is

Algebra.Com
Question 1182118: The equation sec x=−0.5 does NOT have a solution because
it means that cos x = −2 which is outside the range
of the negative value on the right side

the equation is not well formulated

it means that sin x = −2 which is outside the range

Answer by math_tutor2020(3817)   (Show Source): You can put this solution on YOUR website!

If sec(x) = -0.5, then cos(x) = -2 if we apply the reciprocal to both sides. Recall that sec = 1/cos.

Also, recall that the range for cosine is . Meaning that cos(x) between -1 and 1 inclusive of both endpoints. The value -2 is outside this interval, so it's impossible to have cos(x) = -2 where x is a real number.


RELATED QUESTIONS

Find the solution of the equation for [0,2pi] 2(tan(theta))-(sec^2(theta))=0 Here... (answered by Alan3354)
what is the solution set of all angles in [0,2pi) 4 cos^2x-3=0 5 sec^2x-20=0 (answered by stanbon)
if sec x + cos x =5/2 then find the value of sec x - cos x (answered by Alan3354)
Which of the following equation has greatest and smallest number of real solutions? (a) (answered by MathLover1)
Please Help!!!! Which of the following is equivalent to 1/(1-cos(x))- 1/(1+cos(x))? A)... (answered by Alan3354,Edwin McCravy)
Please help me solve this equation: Which of the following is a valid trigonometric... (answered by lwsshak3)
Please Help!!!! Which of the following is equivalent to 1/(1-cos(x))- 1/(1+cos(x))? A)... (answered by Alan3354)
Name all values of θ for which y=secθ is undefined. Give the answer in radians. (answered by Alan3354)
How do you determine the range of a bottom-heavy rational function? The function I need... (answered by josgarithmetic)
Find all solutions of the equation in the interval [0, 2π) 5 sec^2 x − 5 = 0 (answered by Alan3354)