SOLUTION: Find the points of intersection of the line y = 7x-42 and the circle with equation x^2+y^2-4x+6y = 12

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Question 1180172: Find the points of intersection of the line y = 7x-42 and the circle with equation x^2+y^2-4x+6y = 12
Found 2 solutions by ikleyn, mananth:
Answer by ikleyn(52781)   (Show Source): You can put this solution on YOUR website!
.

You substitute y = 7x-42 from the first equation into the second equation.


Doing this way, you obtain a quadratic equation for x.


You solve it and obtain the solutions for x (if they do exist).


Then for each found value of x you find the corresponding value of y, using the first equation.


Having my instructions, the rest is standard mechanical work, which I leave to you.

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To see many other similar solved problems (yours TEMPLATES), look into the lesson
    - Solving systems of algebraic equations of degree 2 and degree 1
in this site.



Answer by mananth(16946)   (Show Source): You can put this solution on YOUR website!
y = 7x-42 and the circle with equation x^2+y^2-4x+6y = 12
substitute y in equation of circle




(x-6)(x-5)=0
x=6, x=5
plug value of x to get values of y
(6,0), (5,-7)
.


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