SOLUTION: Let f(n) = 1/2 + 1/3 + 1/4 + 1/5 + 1/6 + 1/7 + ... 1/n Find a recursive formula for f(n). Do not forget to include any necessary base case(s).

SOLUTION: Let f(n) = 1/2 + 1/3 + 1/4 + 1/5 + 1/6 + 1/7 + ... 1/n Find a recursive formula for f(n). Do not forget to include any necessary base case(s).

Algebra.Com

Question 1176881: Let f(n) = 1/2 + 1/3 + 1/4 + 1/5 + 1/6 + 1/7 + ... 1/n
Find a recursive formula for f(n). Do not forget to include any necessary base case(s).
Answer by ikleyn(52750) (Show Source): You can put this solution on YOUR website!
.


    f(1) = ,

    f(n) = f(n-1) + ,   n = 2, 3, 4, 5, . . .

Solved.

RELATED QUESTIONS
I am working with recursive functions. I do not understand the examples given in the... (answered by stanbon)

The recursive rule for a sequence is f(1)=8 1/2, f(n)=f(n-1)-1/2. How should I find the... (answered by Edwin McCravy)

find the first five values of the recursive function f(1)= 5; f(n) = f(n-1) +... (answered by stanbon)

Given {f(1)=5 and f(n)=f(n-1)+4} find the explicit... (answered by ikleyn)

F(1)=6,f(n)=f(n-1)-5 (answered by ikleyn)

Let f be a function defined by f(n)=2f(n-1)+3f(n-2), where f(1)=3 and f(2) = 1.... (answered by ikleyn)

A sequence has its first term equal to 4, and each term of the sequence is obtained by... (answered by ikleyn)

the recursive rule for a sequence is f(n) = f(n-1)/2 +5. The first term is 4. What is the (answered by ewatrrr)

1. A(n)=-3+(n-1)(5) 2. A(n)=-11+(n-1)(2) 3. A(n)=9+(n-1)(8) 4. A(n)=0.5+(n-1)(3.5) (answered by tommyt3rd)