SOLUTION: let f(x)=-2x^3+3x^2+36x over the closed interval (-3,5) what is the smallest critical point?

SOLUTION: let f(x)=-2x^3+3x^2+36x over the closed interval (-3,5) what is the smallest critical point?

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Question 1169878: let f(x)=-2x^3+3x^2+36x over the closed interval (-3,5) what is the smallest critical point?
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
f'(x)=-6x^2+6x+36
set that equal to 0
6x^2-6x-36=0, multiplying by -1
x^2-x-6=0 dividing by 6 both sides
(x-3)(x+2)=0
x=-2, 3
-2

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