SOLUTION: f(x)=-3x^2+3x-2
a. opens up or opens down
b. vertex =
c axis of symmetry
d. show algebraically how you know the function has no x-intercepts
e internal where it is increasin
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Question 1157414: f(x)=-3x^2+3x-2
a. opens up or opens down
b. vertex =
c axis of symmetry
d. show algebraically how you know the function has no x-intercepts
e internal where it is increasing and decreasing
Found 2 solutions by ikleyn, MathLover1:
Answer by ikleyn(52776) (Show Source): You can put this solution on YOUR website!
.
duplicate.
I just answered it. See the link
https://www.algebra.com/algebra/homework/Functions/Functions.faq.question.1157403.html
Answer by MathLover1(20849) (Show Source): You can put this solution on YOUR website!
a. opens up or opens down
=> coefficient of the is negative
b. vertex =
write equation in vertex form
.......complete square
.......
,
vertex is at (,)
c axis of symmetry
The axis of symmetry always passes through the vertex of the parabola . The x -coordinate of the vertex is the equation of the axis of symmetry of the parabola.
d. show algebraically how you know the function has no x-intercepts
If the discriminant of a quadratic function is less than zero, that function has no real roots, and the parabola it represents does not intersect the x-axis.
if determinant <0
->proven
e. internal where it is increasing and decreasing
in interval (,) is increasing ,and in interval (,) decreasing
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