SOLUTION: Is there any one that knows how to work this problem?
Find the zeros of f.
f(x)= -x^(2)e^(-x)+ 2xe^(-x)
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-> SOLUTION: Is there any one that knows how to work this problem?
Find the zeros of f.
f(x)= -x^(2)e^(-x)+ 2xe^(-x)
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Is there any one that knows how to work this problem?
Find the zeros of f.
To find the zeros substitute 0 for f(x) and solve for x.
Get 0 on the right:
Factor out
Now we use the zero product principle.
There are three factors: ,, and
Setting x = 0 gives one solution, namely x = 0
Setting = 0 gives no solution, since is never 0.
Setting x-2 = 0 gives a second solution, namely x = 2
So there are two zeros, 0 and 2.
Edwin