SOLUTION: The measure of the supplement of angle A is 40 degrees larger than twice the measure of the complement of angle A. What is the sum in degree of the measures of the supplement and c

Question 1132483: The measure of the supplement of angle A is 40 degrees larger than twice the measure of the complement of angle A. What is the sum in degree of the measures of the supplement and complement of angle A?
Answer by Edwin McCravy(20056) (Show Source): You can put this solution on YOUR website!

The measure of the supplement of angle A...

That's 180°-A

So far we have -->                    180°-A

...is...

That's equal =

So far we have -->                     180°-A =

...40 degrees larger than...

that means that we are to add 40° onto what's after "than"

So far we have -->                     180°-A =          +40°  
(skipping a space for what's after "than"):

...twice...

That means that what's after "than" starts with 2× (*two times") 

So far we have -->                     180°-A = 2×       +40°

...the measure of the complement of angle A...

That's (90°-A), so that's what we put after the 2× and before
the +40°

Now we have the finished equation: 
                                       180°-A = 2×(90°-A)+40°

So we solve it

Distribute the 2×

                                       180°-A = 2×90°-2×A+40°
Multiply 2×90° get 180°
                                       180°-A = 180°-2A+40°

Subtract 180° from both sides:

                                           -A = -2A+40°

Add 2A to both sides

                                            A = 40°

...What is the sum in degree of the measures of the supplement...

That's 180°-A
       180°-40°
       140°

...and complement of angle A?...

That's 90°-A
       90°-40°
       50°

Edwin

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