SOLUTION: The function N(x)= 40,000/1+20e^-1.5 describes the number of people, N(t), who become ill with a virus t weeks after its initial outbreak in a town with 40 comma 000 inhabit

Question 1129576: The function N(x)= 40,000/1+20e^-1.5 describes the number of people, N(t), who become ill with a virus t weeks after its initial outbreak in a town with 40 comma 000 inhabitants. The horizontal asymptote in the graph indicates that there is a limit to the epidemic's growth. Complete parts (a) through (c) below.
a. How many people became ill with the virus when the epidemic began? (When the epidemic began, t=0.)
When the epidemic began, approximately 1905 people were ill with the virus.
(Round to the nearest person as needed.). I got the answer!
b. How many people were ill by the end of the second week?
By the end of the second week, approximately____________people were ill with the virus.
(Round to the nearest person as needed.)
ASAP Please and thank you!
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
N(x)= 40,000/1+20e^-1.5t, editing in the t
When t=0, e^0=1
40000/21=1905
after two weeks I am assuming t=14 and this is in days not hours or some other unit.
=40000/(1+20e^(-21)), the 21 coming from 14*(1.5), and that number is essentially 0, so the denominator is 1.
That makes N(x)=40000 people, if the above assumptions are correct. It is important to know where the x is.
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SOLUTION: The function N(x)= 40,000/1+20e^-1.5 describes the number of&#8203; people, N(t), who become ill with a virus t weeks after its initial outbreak in a town with 40 comma 000 inhabit

SOLUTION: The function N(x)= 40,000/1+20e^-1.5 describes the number of people, N(t), who become ill with a virus t weeks after its initial outbreak in a town with 40 comma 000 inhabit