She only gave one solution. Also she made some illegal assumptions. There are 8 altogether, although there are really only 4, because the two parentheses on the right can be in reverse order. That would be a, b and c trading places with d, e and f, respectively. For instance, solutions 1 and 3 below are essentially the same. Here are all 8 possibilities (4 essentially): 1. x² - y² + x + 5y - 6 = (-x - y + 2)(-x + y - 3), in which a=-1, b=-1, c=2, d=-1, e=1, f=-3, m=1 2. x² - y² - x + 5y - 6 = (-x - y + 3)(-x + y - 2), in which a=-1, b=-1, c=3, d=-1, e=1, f=-2, m=-1 3. x² - y² + x + 5y - 6 = (-x + y - 3)(-x - y + 2), in which a=-1, b=1, c=-3, d=-1, e=-1, f=2, m=1 4. x² - y² - x + 5y - 6 = (-x + y - 2)(-x - y + 3), in which a=-1, b=1, c=-2, d=-1, e=-1, f=3, m=-1 5. x² - y² - x + 5y - 6 = (x - y + 2)(x + y - 3), in which a=1, b=-1, c=2, d=1, e=1, f=-3, m=-1 6. x² - y² + x + 5y - 6 = (x - y + 3)(x + y - 2), in which a=1, b=-1, c=3, d=1, e=1, f=-2, m=1 7. x² - y² - x + 5y - 6 = (x + y - 3)(x - y + 2), in which a=1, b=1, c=-3, d=1, e=-1, f=2, m=-1 8. x² - y² + x + 5y - 6 = (x + y - 2)(x - y + 3), in which a=1, b=1, c=-2, d=1, e=-1, f=3, m=1 Edwin