SOLUTION: For the function, the vertex of the graph is given. Find the unknown coefficients. y=x^2+bx+c; (-4,5)

Question 1125818: For the function, the vertex of the graph is given. Find the unknown coefficients.
y=x^2+bx+c; (-4,5)
Found 2 solutions by ikleyn, josgarithmetic:
Answer by ikleyn(52864) (Show Source): You can put this solution on YOUR website!
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From the condition, y = a*(x+4)^2 + 5 = ax^2 + 8ax + 16a + 5. Comparing coefficients, you conclude that a= 1, b= 8, c= 21.

Answer by josgarithmetic(39627) (Show Source): You can put this solution on YOUR website!
-------left side is in "vertex" form and right side is the variable quadratic trinomial. Multiply the left side and simplify. Compare terms.
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