SOLUTION: If a rock is thrown upward with an initial velocity of 64 ft/second from the top of a 25-foot building.
1) write the hight (s) equation using this information.
2) how high is the
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-> SOLUTION: If a rock is thrown upward with an initial velocity of 64 ft/second from the top of a 25-foot building.
1) write the hight (s) equation using this information.
2) how high is the
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Question 111951: If a rock is thrown upward with an initial velocity of 64 ft/second from the top of a 25-foot building.
1) write the hight (s) equation using this information.
2) how high is the rock after one second?
3) after how many seeconds will the graph reach maximum hight?
4) what is the maximum hight? Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! If a rock is thrown upward with an initial velocity of 64 ft/second from the top of a 25-foot building.
:
:
1) write the hight (s) equation using this information.
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This will be a quadratic equation: s = -16t^2 + 64t + 25
S is the height after t seconds
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The three terms of the above equation represent:
-16t^2: the force of gravity, negative because it's pulling down
64t: the velocity of the rock thrown upward, positive because it is going up
25: the height of the building where all this takes place
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2) how high is the rock after one second?
Substitute 1 for t in the equation and find s
s = -16(1^2) + 64(1) + 25
s = -16 + 64 + 25
s = 73 ft after 1 second
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3) after how many seconds will the graph reach maximum height?
This will occur at the axis of symmetry: Remember x = -b/(2a)
t = -64/2(-16)
t = -64/-32
t = + 2 seconds
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4) what is the maximum height?
This occurs when t = 2; substitute 2 for t in the equation, find s
s = -16(2^2) + 64(2)+25
s = -16(4) + 128 + 25
s = -64 + 128 + 25
s = +89 ft is the maximum
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A graphical presentation would be:
Y axis is the height and x axis is the time in seconds
