SOLUTION: F(x) = x^2-4 and G(x) =square root x Explain why GoF does not exist.

Question 1091723: F(x) = x^2-4 and G(x) =square root x
Explain why GoF does not exist.
Found 2 solutions by rothauserc, ikleyn:
Answer by rothauserc(4718) (Show Source): You can put this solution on YOUR website!
GoF = square root(x^2 -4)
:
GoF is not defined for values of x, where -2 < x < 2 because the square root of a negative number is not defined over the Real numbers
:

Answer by ikleyn(52932) (Show Source): You can put this solution on YOUR website!
.
GoF(x) does not exist at -2 < x < 2.

But it DOES exist at all other x.

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