SOLUTION: Suppose $P(x)$ is a polynomial of smallest possible degree such that:
$\bullet$ $P(x)$ has rational coefficients
$\bullet$ $P(-3) = P(\sqrt 7) = P(1-\sqrt 6) = 0$
$\bullet
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Question 1075770: Suppose $P(x)$ is a polynomial of smallest possible degree such that:
$\bullet$ $P(x)$ has rational coefficients
$\bullet$ $P(-3) = P(\sqrt 7) = P(1-\sqrt 6) = 0$
$\bullet$ $P(-1) = 8$
Determine the value of $P(0)$.
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
Rational coefficients and irrational roots means the irrational roots occur as conjugate pairs.
So,
So then,
.
.
.
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