SOLUTION: The height in feet of a water rocket launched from the ground is given by the function h(t)=−16t2+96t where t represents the number of seconds after launch. What is the maxim

Question 1072632: The height in feet of a water rocket launched from the ground is given by the function h(t)=−16t2+96t where t represents the number of seconds after launch. What is the maximum height attained by the rocket?
Answer by ikleyn(52787) (Show Source): You can put this solution on YOUR website!
.

The maximal height is the vertex of the parabola

h(t) = 

Its t-value is t =  =  = 3.

So, the maximal height is achieved at t = 3 seconds.

The value of the maximal height is  =  = 144 ft.

Answer. The maximal height is 144 ft at t = 3 seconds.

Plot y = -16*t^2 + 96t

See the lessons on a projectile thrown/shot/launched vertically up
    - Problem on an arrow shot vertically upward
    - Problem on a ball thrown vertically up from the top of a tower

Also, you have this free of charge online textbook in ALGEBRA-I in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this textbook under the topic "Projectiles launched/thrown and moving vertically up and dawn".

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SOLUTION: The height in feet of a water rocket launched from the ground is given by the function h(t)=&#8722;16t2+96t where t represents the number of seconds after launch. What is the maxim

SOLUTION: The height in feet of a water rocket launched from the ground is given by the function h(t)=−16t2+96t where t represents the number of seconds after launch. What is the maxim