Given:  n(x) = x2-9 
        m(x) = x+3 
        p(x) = √x+1
 
Use the functions to find:
 
a. (n-m)(-6)

First we find (n-m)(x)

(n-m)(x) = 

(n-m)(x) = n(x) - m(x) = 

(n-m)(x) = (x2-9) - (x+3) = 

(n-m)(x) = x2-9-x-3 = 

(n-m)(x) = x2-x-12 

Now substitute (-6) for x

(n-m)(-6) = (-6)2-(-6)-12

(n-m)(-6) = 36+6-12

(n-m)(-6) = 30

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b.  (n•p)(0) 

First we find (n•p)(x)

(n•p)(x) = n(x)•p(x)

(n•p)(x) = (x2-9)•(√x+1)

Now substitute 0 for x

(n•p)(0) = (02-9)•√0+1

(n•p)(0) = (0-9)•√1

(n•p)(0) = (-9)•1

(n•p)(0) = -9

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c. (0) 

First we find (x) 

(x) = 

(x) = 

Now substitute 0 for x

(0) = 

(0) = 

(0) = 

Edwin