SOLUTION: hi, i am having trouble solving these , would you be so kind to explain how to determine whether the equation defines Y as a function of X: 1. 6x+3y^2=7 2. square

Question 1050162: hi, i am having trouble solving these , would you be so kind to explain how to determine whether the equation defines Y as a function of X:
1. 6x+3y^2=7
2. square root (6x) +y=5
3. 5x^2+y^3=27
4. 4x+ IyI=3

Thanks in advance it would help tremendously to understand on how to solve these
Found 2 solutions by stanbon, advanced_Learner:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
explain how to determine whether the equation defines Y as a function of X:
1. 6x+3y^2=7
6x = -3y^2+7
x = -(1/2)y^2 + (7/6)
Parabola opening to the left.
Not a function.
---------------------------------------
2. square root (6x) +y=5
y = -sqrt(6x) + 5
Defined for x >= 0
As x gets larger y just gets more and more negative.

Is a function
---------------------------------------
3. 5x^2+y^3=27
y = (-5x^2+27)^(1/3)

Cubics tend to be functions.
-----------------------
4. 4x+ IyI=3
Is that the "greatest integer" symbol?
If so, it looks like a step-function.
Is a function
-----------
Cheers,
Stan H.
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Answer by advanced_Learner(501) (Show Source): You can put this solution on YOUR website!
hi, i am having trouble solving these , would you be so kind to explain how to determine whether the equation defines Y as a function of X:
1. 6x+3y^2=7
2. square root (6x) +y=5
3. 5x^2+y^3=27
4. 4x+ IyI=3
solve for y
1.
1.
1.
1.
2.
2.
3.
3.
3.
4.
4.
meaning

or

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