SOLUTION: Find the vertex, and the x and y intercepts by completing the following: f(x) = -x^2 + 6x - 8
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-> SOLUTION: Find the vertex, and the x and y intercepts by completing the following: f(x) = -x^2 + 6x - 8
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Question 104962
:
Find the vertex, and the x and y intercepts by completing the following:
f(x) = -x^2 + 6x - 8
Answer by
MathLover1(6611)
(
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):
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Completing the Square to Get a Quadratic into Vertex Form
Start with the given equation
Add
to both sides
Factor out the leading coefficient
Take half of the x coefficient
to get
(ie
).
Now square
to get
(ie
)
Now add and subtract this value inside the parenthesis. Doing both the addition and subtraction of
does not change the equation
Now factor
to get
Distribute
Multiply
Now add
to both sides to isolate y
Combine like terms
Now the quadratic is in vertex form
where
,
, and
. Remember (h,k) is the vertex and "a" is the stretch/compression factor.
Check:
Notice if we graph the original equation
we get:
Graph of
. Notice how the vertex is (
,
).
Notice if we graph the final equation
we get:
Graph of
. Notice how the vertex is also (
,
).
So if these two equations were graphed on the same coordinate plane, one would overlap another perfectly. So this visually verifies our answer.