SOLUTION: A quadratic function is given by y=5x^2+7+11. For what domain values of y, the solution of x will be a real number?

Question 1047672: A quadratic function is given by y=5x^2+7+11. For what domain values of y, the solution of x will be a real number?
Answer by josgarithmetic(39627) (Show Source): You can put this solution on YOUR website!
All real numbers for x will give a RANGE of real numbers for y. The equation has a restriction for its RANGE. Range is all values greater than the y-coordinate of the vertex.

, Square completed, now in standard form.
The range is all real numbers greater than or equal to .
RELATED QUESTIONS
Let K be a real number, and consider the quadratic equation (k+1)x^2+4kx+2=0 a. Show... (answered by robertb)

what is the range of the function rule y=5x-2 for the domain {0.5, 11} (answered by Mr.positive)

1. This equation is given in vertex form, write it in standard form. f(x)= -(3/4)(x+2)^2 (answered by josgarithmetic)

State the domain and range of f(x)=2^x. Here is what I did.....The domain of f(x)=2^x... (answered by stanbon)

2) Solve for x. 5x^2=-19x-12... (answered by Alan3354,ewatrrr)

What is the domain of the function y = square root(x - 7)? A. x ≥ 7 B. x... (answered by rapaljer)

Find the values of a in the domain of f for which f(a) equals the given number. f(x)... (answered by josgarithmetic)

What is the domain of the following quadratic function? f(x)=2x^2+5x-7? (answered by KMST)

Quadratic function 1) A function that has a local maximum will have ___< 0 (what... (answered by MathLover1)