SOLUTION: What is the inverse equation for:
h(x)= (2x-1)/(x+1)
Algebra.Com
Question 1046875: What is the inverse equation for:
h(x)= (2x-1)/(x+1)
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
What is the inverse equation for:
h(x)= (2x-1)/(x+1)
---------------
1st: Interchange x and y to get:
x = (2y-1)/(y+1)
------
2nd: Solve for "y"::
xy+x = 2y-1
----
xy-2y = -(x+1)
y(x-2) = -(x+1)
y = -(x+1)/(x-2)
That is the inverse.
--------------------------
Cheers,
Stan H.
------------
RELATED QUESTIONS
Algebraically find the equation of the inverse function for: h(x) =... (answered by atif.muhammad)
What is the inverse function of... (answered by tommyt3rd)
What is the inverse function of h(x) = 2 * 5throot((1-x)^3) +... (answered by It is costly)
Write the inverse equation of... (answered by tommyt3rd)
what is the inverse function of h(x)=9x/x-1 and what is the domain and range of the... (answered by rothauserc)
determine their inverse function:
h(x)=... (answered by Alan3354)
what is the inverse operation for... (answered by msmika31)
If h(x) = 6, for the function h(x) = 2x + 1, what is the value of... (answered by Cromlix,fractalier)
how to solve for x the equation is H(x)x^4 -2x^2 -1 when... (answered by chessace)