Since it has vertical asymptotes at the lines x = 3 and x = -3, the
denominator is (x-3)(x+3) or x²-9

Since it has horizontal asymptote y = 1, the leading term of the numerator
must by x²

So it has form:

, for some B and C

Since it has x-intercept 5, it passes through the point (5,0),
so we substitute (x,y) = (5,0)







Multiply both sides by 16



Since it has y-intercept -5/9, it passes through the point (0,-5/9),
so we substitute (x,y) = (0,-5/9)







Multiply through by -9



Substitute in











So 



becomes




Edwin