SOLUTION: When the function y=h(x)=ax^2+bx+c is graphed in the x-y plane, the result is a parabola with vertex at (4,7). If h(2)=0, which of the following must also equal to 0? a.)h(5) b

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Question 1045147: When the function y=h(x)=ax^2+bx+c is graphed in the x-y plane, the result is a parabola with vertex at (4,7). If h(2)=0, which of the following must also equal to 0?
a.)h(5)
b.) h(6)
c.) h(8)
d.) h)9)
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39620)   (Show Source): You can put this solution on YOUR website!
You make better sense of this when put h into standard form.

, standard form.

and you have a point, (2,0).
Think of how a parabola is symmetric.
Can you judge that ?








Find BOTH zeros!
Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!

When the function y=h(x)=ax^2+bx+c is graphed in the x-y plane, the result is a parabola with vertex at (4,7). If h(2)=0, which of the following must also equal to 0?
a.)h(5)
b.) h(6)
c.) h(8)
d.) h)9)


 ------- Vertex form 

 ------ Substituting 0 for y, 2 for x, 4 for h, and 7 for k  



- 7 = 4a_______ = a

Function:  



Now, you can substitute each answer choice into the above function to see which one gives a value of 0, or you can easily look at the equation

and determine WHAT VALUE x can be replaced with, and when combined with - 4, and the result is squared, results in a value of 4. That MUST be 6.

Therefore, it must be  

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