SOLUTION: Given the function f(x) = x^2-8 over x-3, if x = -2, what is f(x)? What point is on the graph of f?

Question 1044934: Given the function f(x) = x^2-8 over x-3, if x = -2, what is f(x)? What point is on the graph of f?

Answer by Theo(13342) (Show Source): You can put this solution on YOUR website!
f(x) = (x^2 - 8) / (x - 3)

to find f(-2), replace x with -2 to get:

f(-2) = ((-2)^2 - 8) / (-2 - 3)

simplify to get:

f(-2) = (4 - 8) / (-5)

simplify further to get:

f(-2) = -4 / -5

simplify further to get:

f(-2) = 4/5

the coordinate point on the graph will be (-2, 4/5)

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