SOLUTION: The graph of the function f(x)=mx+b contains the points (r,3) and (7,s). Express s in terms of r if the graph is parallel to the line 3x-2y=7. The answer is s=-3/2r+27/2 I just don
Algebra.Com
Question 1044401: The graph of the function f(x)=mx+b contains the points (r,3) and (7,s). Express s in terms of r if the graph is parallel to the line 3x-2y=7. The answer is s=-3/2r+27/2 I just don't know how to get there thank you
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
The graph of the function f(x)=mx+b contains the points (r,3) and (7,s). Express s in terms of r if the graph is parallel to the line 3x-2y=7. The answer is s=-3/2r+27/2
----------
Parallel lines have the same slope, m.
--
Find the slope of the line 3x-2y=7
Put it in slope-intercept form, y = mx + b
That means solve for y.
3x-2y=7
3x = 2y + 7
2y = 3x -7
y = (3/2)x - 7/2
Slope = 3/2
----------
Find the slope of the 2 points.
Slope = diffy/diffx = (s-3)/(7-r)
So (s-3)/(7-r) = 3/2
Cross multiply.
2(s-3) = 3(7-r)
2s-6 = 21-3r
2s = -3r + 27
s = (-3/2)r + 27/2
RELATED QUESTIONS
The graph of the function f(x)=mx+b contains the points (a,2) and (-5,b) express a in... (answered by solver91311)
Is the line through the points R (-1,3) and S (2.-7) parallel to the graph of the line... (answered by Alan3354)
The graph of a function F(x)=mx + b contains the points (5,15) and (-3,-5). Find... (answered by rmromero)
The graph of the function f(x)=mx+b contains the points (5,1) and (-10,-11). Find m and... (answered by mananth)
If the graph of 3x-5y=s passes through points (3,1) and (5,r), what is the value of... (answered by ramkikk66)
(1) x+3y=6 (2) x=2 (3) y=-1 (4)Determine wether graphs of pairs of line are parallel... (answered by Fombitz)
The sketch shows the graph of a function f, which is a straight line defined by y = mx +k (answered by Alan3354)
{{{f(x)=x^2}}}, g(x)=x-1, {{{ h(x)=sqrt(x)
a. give the domain and range of each... (answered by stanbon)
f is a one-to-one function. The graph of f(x) contains the points (-16,-3).
Therefore... (answered by jim_thompson5910)