SOLUTION: Given that f(x)=x^2-3x and g(x)=x+10, find f+g= f-g= f*g= f/g=

SOLUTION: Given that f(x)=x^2-3x and g(x)=x+10, find f+g= f-g= f*g= f/g=

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Question 1034683: Given that f(x)=x^2-3x and g(x)=x+10, find
f+g=
f-g=
f*g=
f/g=
Answer by fractalier(6550) (Show Source): You can put this solution on YOUR website!
For f(x)=x^2-3x and g(x)=x+10,
f+g= x^2-3x + x+10
f-g= x^2-3x - (x+10)
f*g= (x^2-3x)(x+10)
f/g= (x^2-3x)/(x+10)
I plugged them all in, now you finish...
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