SOLUTION: For the nonzero numbers a, b, and c, define J(a,b,c) = a/b + b/c + c/a.
Find J(2,12, 9).
Algebra.Com
Question 1029537: For the nonzero numbers a, b, and c, define J(a,b,c) = a/b + b/c + c/a.
Find J(2,12, 9).
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
.
.
.
RELATED QUESTIONS
is it true for all nonzero real numbers a,b and c that
a/b+c = a/b +... (answered by greenestamps,ikleyn)
is it true for all nonzero real numbers a,b and c that
a/(b+c) =a/b +... (answered by ikleyn)
The compound inequality 4j + 2 > 6 and j < 3 simplifies to:
A. j > 1 or j >... (answered by Fombitz)
For nonzero numbers a, b, and c, b is 1/3 of a, and c is twice b. What is the value of... (answered by MathLover1)
please help me solve a/b=c solve for b and h-4/j=k solve for... (answered by stanbon)
What is the value of j in the equation √ j + √ j + 14 = 3√ j +... (answered by srinivas.g,MathLover1)
You are confronted with the following formula:
A * [(B + C)(D - E) - F(G*H) ] / J = 10
(answered by 303795)
find nonzero integers A, B, C such that Ax^2+Bx+C=0 has solutions B and... (answered by greenestamps)
• U = {a, b, c, d, e, f, g, h, i, j, k}
• A = {a, c, d, f, g, i}
• B = {b, c, d, f,... (answered by stanbon)