SOLUTION: Hello. Please, if someone could give me an explanation on how to solve this problem, I'd really appreciate.
Suppose that you are given an open top box with the square base. Let
Algebra.Com
Question 1024986: Hello. Please, if someone could give me an explanation on how to solve this problem, I'd really appreciate.
Suppose that you are given an open top box with the square base. Let x be the length of the side of the base and let the volume of the box be V=1. Express the surface area of the box in terms of two power functions of x.
Thank you very much.
Answer by josgarithmetic(39620) (Show Source): You can put this solution on YOUR website!
Base surface but not a top surface. You have volume of 1 unit of whatever this volume unit may be, as V=1.
The dimension for height may be any variable you choose. Try assigning y for the height.
---------still two unknown variables, x and y.
The question to answer is, what is the expression for the surface area?
Four of the surfaces each are , and the base area is .
-
The surface area for this box is . You already know something about y, so you can substitute for y:
but since you are asked for all power functions of x, express this area as .
RELATED QUESTIONS
Hello, I would appreciate if someone could help me solve this math problem please. Thank... (answered by stanbon,TimothyLamb,Hawksfan)
Could someone show me how to put these problems on paper not just the answers because... (answered by solver91311)
Hello, could someone help me with this problem? I'd really appreciate a step-by-step... (answered by Alan3354)
Need help, got a test on Tuesday could you please show me how to work this problem.... (answered by vleith)
Find an equation of the parabola that has vertex (1,2) and focus (-1,2).
I dont know... (answered by scott8148)
Hello !
Can you please help me with this? I just don't get it... Iwould really... (answered by Fombitz)
Find an equation of the parabola that has vertex (1,2) and focus (-1,2).
I dont know... (answered by scott8148)
Question: An angle measures 15° more than twice its supplement. Find the measure of the... (answered by Earlsdon,vosotroslovely)
log((0.53)/x^2))=((-4.86)/(1.98)(10^-3))((1/200)-(1/400))
I havent done this type of... (answered by Edwin McCravy)