SOLUTION: Find an equations of the line containing the point (1,-2) and parallel to the line x+2y=-6

SOLUTION: Find an equations of the line containing the point (1,-2) and parallel to the line x+2y=-6

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Question 1017896: Find an equations of the line containing the point (1,-2) and parallel to the line x+2y=-6
Answer by fractalier(6550) (Show Source): You can put this solution on YOUR website!
The slope of x+2y=-6 is found by m = -A/B = -1/2. We need the same slope.
Then we plug into
y = mx + b to find b and get
-2 = (-1/2)(1) + b
so that
b = -3/2
and our equation becomes
y = (-1/2)x - 3/2
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