SOLUTION: A water ballon is launched from a launcher, up into the air from a platform. The height of the balloon in feet, is a function of the time in seconds since it was launched: f(t)= 16

Question 1015369: A water ballon is launched from a launcher, up into the air from a platform. The height of the balloon in feet, is a function of the time in seconds since it was launched: f(t)= 16t^2+V0t+H0 where V0 represents the initial upward velocity of the launch, and H0 represents the height of balloon right when it is launched. Lorenzo launches his water balloon with an initial upward velocity of 80 ft per second. The initial height of the water balloon is 5ft off the ground what is the maximum height of the water balloon?
Answer by KMST(5328) (Show Source): You can put this solution on YOUR website!
You are missing a minus sign in front of the .
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JUST USING ALGEBRA:
.

APPLYING A FORMULA:
is a quadratic function.
A quadratic function with has a maximum at ,
so, in this case, with ,
the maximum happens at .
The maximum is

So, the maximum height of the water balloon is .

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