SOLUTION: My book from Granthum U does not show how to do this one. Find functions f and g so that h(x)=(f'g)(x) {{{h(x)=6/x^2 + 8}}} Thanx

Question 101232: My book from Granthum U does not show how to do this one.
Find functions f and g so that h(x)=(f'g)(x)

Thanx
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
h(x)=6/x^2 + 8
---------
I'll assume your problem is as follows:
h(x) = [6/x^2] + 8
--------------------
You want f{g(x)]=h(x)
Let g(x)= 1/x^2
Then Let f(x)=6x + 8
----------
Then f[g(x)]
= f[1/x^2]
=6(1/x^2)+8
= [6/x^2]+8
=h(x)
==============
Cheers,
Stan H.

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