SOLUTION: Jill has a swimming pool in her backyard. It is shaped like a rectangle and measures approximately 16.3 feet wide and 26.2 feet long. It is an average of 5 feet deep. During a few

Question 1012273: Jill has a swimming pool in her backyard. It is shaped like a rectangle and measures approximately 16.3 feet wide and 26.2 feet long. It is an average of 5 feet deep. During a few hot weeks during the summer, some water evaporates from the pool, and Jill needs to add 8 inches of water to the depth of the pool, using her garden hose. Although her water pressure varies, the water flows through Jill�s garden hose at an average rate of 10 gallons/minute.
1. Convert the dimensions of the pool to meters. Round all meter measurements to one decimal place (nearest tenth of a meter).
2. How many liters will Jill need to add to her pool to return the water level to its original depth? How many gallons of water is this? Reminder: Volume = Length x Width x Depth
3. How long will Jill need to run the hose? Express your answer in hours and minutes.

Answer by macston(5194) (Show Source): You can put this solution on YOUR website!
.
1.
L=length=26.2 feet=8.0 meters
W=width=16.3 feet=5.0 meters
D=Depth=5 feet=1.5 meters
Added water depth=8 inches=0.2 meters
Hose rate=10 gal/min=37.9 liters/min
.
2.
Amount added=(8.0m)(5.0m)(0.2m)=8m^3=8000 liters=2113.4 gallons
.
3.
8000 liters/(37.9 liters/min)=211.1 min= 3 hours 31.1 minutes
2113 gallons/(10gal/min)=211.3 min=3 hours 31.3 minutes
12 second discrepancy in fill time due to rounding.
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