SOLUTION: I am stuck on this problem. If I can see this worked out it would help a lot!
If f(x) = (1/x - 9x) / (1+3x), what is f(1/x).
My book says the answer is x-3 but I cannot get
multiply numerator and denominator of this equation by x to get:
f(1/x) =
x^2 - 9 = (x-3) * (x+3)
equation becomes:
f(1/x) =
the x+3 in the numerator and in the denominator cancel out and you are left with:
f(1/x) = (x-3)
Answer by rothauserc(4718) (Show Source): You can put this solution on YOUR website! If f(x) = (1/x - 9x) / (1+3x), what is f(1/x).
f(1/x) = ((1/(1/x))-9(1/x)) / (1+3(1/x)) =
(x - (9/x)) / (1 + 3(1/x)) =
((x^2-9) / x) / ((x+3) / x)) =
(((x+3)(x-3)) / x) * (x / (x+3)) =
(x-3)
Answer by MathTherapy(10556) (Show Source): You can put this solution on YOUR website!
I am stuck on this problem. If I can see this worked out it would help a lot!
If f(x) = (1/x - 9x) / (1+3x), what is f(1/x).
My book says the answer is x-3 but I cannot get this same answer.