SOLUTION: The solution set in interval notation of the inequality 16x-x^3≥0 is:
A) [-4, 4]
B) (-∞, -2]U[0, 4)
C) (-∞, 0]U[1, 4)
D) (-∞, 4]
E) (-∞, -4]U[
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Question 1006083: The solution set in interval notation of the inequality 16x-x^3≥0 is:
A) [-4, 4]
B) (-∞, -2]U[0, 4)
C) (-∞, 0]U[1, 4)
D) (-∞, 4]
E) (-∞, -4]U[0, 4]
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
Critical x values: -4,0,4;
? (-infinity,-4] ?
(-)(-)(+)>=0
TRUE
[-4,0] ?
Try -1.
(-1)(4-1)(4-(-1))=(-1)(3)(5)>=0
FALSE
[0,4] ?
Try 1
1*(4+1)(4-1)=1*5*3>=0
TRUE
[4, infinity) ?
5*(4+5)(4-5)=Negative>=0
FALSE
Solution set is (-infinity, -4] U [0,4].
Choice E.
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