SOLUTION: it is given that the axis of symmetry of the graph of the function y=x^2+kx+5 is x＝-3. Find the value of k.
Algebra.Com
Question 1005918: it is given that the axis of symmetry of the graph of the function y=x^2+kx+5 is x＝-3. Find the value of k.
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
Complete the square to get to vertex form,
The vertex lies on the axis of symmetry so when ,
RELATED QUESTIONS
It is given that the axis of symmetry of the graph of the function y=x^2+kx+5＝-3.... (answered by MathLover1)
Consider the quadratic function y＝kx(x-2)+3. If its optimum value is 4, find the... (answered by josgarithmetic)
Find all k so that the graph of y = -1/4x^2 +kx -9 is tangent to the... (answered by Alan3354)
Find the value of k such that x-2 is a factor of kx^3 - kx^2 + x+2
(answered by ikleyn)
if x^6+kx^5+x^4+kx^3+3x^2-k+2 is a multiple of (x-k) find the value of... (answered by jsmallt9)
If the graph of the parabola y=kx^2+6x+k+8 is tangent to x-axis, then what is the... (answered by oscargut)
Find the value of k so that (x-5) is a factor of kx^3 - 17x^2 - 4kx +... (answered by josgarithmetic)
For what positive value of k is the graph of y = kx^2 + 6x + k +8 tangent to the x... (answered by drk)
given the equation Kx^2+(k+3)x+3-4k=0 find the value of k given that one root is 2 (answered by jim_thompson5910)