SOLUTION: Find the equation of the tangent line to the curve {{{(x-y)^2}}}{{{""=""}}}{{{2x+1}}} at the point (4,1).

Question 1003954: Find the equation of the tangent line to the curve
at the point (4,1).
Answer by Edwin McCravy(20054) (Show Source): You can put this solution on YOUR website!
Find the equation of the tangent line to the curve

at the point (4,1).



We take the derivative implicitly:



Substitute (x,y) = (4,1)



















The derivative at a point is the slope of the
line tangent to the curve at the point, therefore
the slope of the tangent line is 



We use the point-slope formula for the equation
of the tangent line:



where (x₁,y₁) = (4,1)

[Do not substitute for x and y, but leave them 
as variables]









, graphed in green below:



Edwin

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